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	<title>The Neotropic Book of Physics</title>
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		<title>The Neotropic Book of Physics</title>
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		<title>State vectors</title>
		<link>http://neotropic.wordpress.com/2011/07/21/state-vectors/</link>
		<comments>http://neotropic.wordpress.com/2011/07/21/state-vectors/#comments</comments>
		<pubDate>Thu, 21 Jul 2011 17:39:35 +0000</pubDate>
		<dc:creator>phalacrocorax</dc:creator>
				<category><![CDATA[Quantum Physics]]></category>

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		<description><![CDATA[A state vector is a vector in a Hilbert space that complete describes the state of a quantum system. Given an orthogonal basis , each one of its vectors representing a different possible outcome of a complete measurement of the system, any state vector can be written as a linear combination of the basis states [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=neotropic.wordpress.com&amp;blog=18211513&amp;post=2257&amp;subd=neotropic&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>A state vector <img src='http://s0.wp.com/latex.php?latex=%5Cleft%7C+%5Cpsi+%5Cright%5Crangle&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;left| &#92;psi &#92;right&#92;rangle' title='&#92;left| &#92;psi &#92;right&#92;rangle' class='latex' /> is a vector in a Hilbert space that complete describes the state of a quantum system. Given an orthogonal basis <img src='http://s0.wp.com/latex.php?latex=%5Cleft%7C+i+%5Cright%5Crangle&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;left| i &#92;right&#92;rangle' title='&#92;left| i &#92;right&#92;rangle' class='latex' />, each one of its vectors representing a different possible outcome of a complete <a href="http://neotropic.wordpress.com/2011/05/09/measurement-in-quantum-mechanics/">measurement</a> of the system, any state vector can be written as <a href="http://neotropic.wordpress.com/2011/03/14/linear-combination/">a linear combination</a> of the basis states with complex coefficients:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cleft%7C+%5Cpsi+%5Cright%5Crangle+%3D+%5Csum_i+%5Calpha_i+%5Cleft%7C+i+%5Cright%5Crangle&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;left| &#92;psi &#92;right&#92;rangle = &#92;sum_i &#92;alpha_i &#92;left| i &#92;right&#92;rangle' title='&#92;displaystyle &#92;left| &#92;psi &#92;right&#92;rangle = &#92;sum_i &#92;alpha_i &#92;left| i &#92;right&#92;rangle' class='latex' />.</p>
<p>In case the measurement can yield continuous results, the summation can be replaced by an integral:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cleft%7C+%5Cpsi+%5Cright%5Crangle+%3D+%5Cint+dx%5C%3B+%5Calpha%28x%29+%5Cleft%7C+x+%5Cright%5Crangle&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;left| &#92;psi &#92;right&#92;rangle = &#92;int dx&#92;; &#92;alpha(x) &#92;left| x &#92;right&#92;rangle' title='&#92;displaystyle &#92;left| &#92;psi &#92;right&#92;rangle = &#92;int dx&#92;; &#92;alpha(x) &#92;left| x &#92;right&#92;rangle' class='latex' />.</p>
<p>In the most general case, the basis may contain both continuous and discrete labels:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cleft%7C+%5Cpsi+%5Cright%5Crangle+%3D+%5Csum_i+%5Cint+dx%5C%3B+%5Calpha_i%28x%29+%5Cleft%7C+i%3B+x+%5Cright%5Crangle&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;left| &#92;psi &#92;right&#92;rangle = &#92;sum_i &#92;int dx&#92;; &#92;alpha_i(x) &#92;left| i; x &#92;right&#92;rangle' title='&#92;displaystyle &#92;left| &#92;psi &#92;right&#92;rangle = &#92;sum_i &#92;int dx&#92;; &#92;alpha_i(x) &#92;left| i; x &#92;right&#92;rangle' class='latex' />.</p>
<br />Filed under: <a href='http://neotropic.wordpress.com/category/physics/quantum-physics/'>Quantum Physics</a>  <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gocomments/neotropic.wordpress.com/2257/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/comments/neotropic.wordpress.com/2257/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godelicious/neotropic.wordpress.com/2257/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/delicious/neotropic.wordpress.com/2257/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gofacebook/neotropic.wordpress.com/2257/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/facebook/neotropic.wordpress.com/2257/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gotwitter/neotropic.wordpress.com/2257/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/twitter/neotropic.wordpress.com/2257/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gostumble/neotropic.wordpress.com/2257/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/stumble/neotropic.wordpress.com/2257/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godigg/neotropic.wordpress.com/2257/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/digg/neotropic.wordpress.com/2257/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/goreddit/neotropic.wordpress.com/2257/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/reddit/neotropic.wordpress.com/2257/" /></a> <img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=neotropic.wordpress.com&amp;blog=18211513&amp;post=2257&amp;subd=neotropic&amp;ref=&amp;feed=1" width="1" height="1" />]]></content:encoded>
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			<media:title type="html">phalacrocorax</media:title>
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		<title>Characteristic function of a Gaussian distribution</title>
		<link>http://neotropic.wordpress.com/2011/07/20/characteristic-function-of-a-gaussian-distribution/</link>
		<comments>http://neotropic.wordpress.com/2011/07/20/characteristic-function-of-a-gaussian-distribution/#comments</comments>
		<pubDate>Wed, 20 Jul 2011 20:05:46 +0000</pubDate>
		<dc:creator>phalacrocorax</dc:creator>
				<category><![CDATA[Statistics]]></category>

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		<description><![CDATA[The characteristic function of a Gaussian probability distribution will simply be simply the result of the following integral: . The exponentials inside the integral can be turned into a single Gaussian by completing squares: . The remaining integral in can be easily solved as the integral of a Gaussian: . This is simply another Gaussian [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=neotropic.wordpress.com&amp;blog=18211513&amp;post=2248&amp;subd=neotropic&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>The <a href="http://neotropic.wordpress.com/2011/01/10/characteristic-function/">characteristic function</a> of a <a href="http://neotropic.wordpress.com/2011/07/20/gaussian-probability-distribution/">Gaussian probability distribution</a> will simply be simply the result of the following integral:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+F%28k%29+%3D+%5Cfrac%7B1%7D%7B%5Csqrt%7B2%5Cpi%5Csigma%5E2%7D%7D+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+e%5E%7B-%28x-%5Cmu%29%5E2%2F2%5Csigma%5E2%7D+e%5E%7Bikx%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle F(k) = &#92;frac{1}{&#92;sqrt{2&#92;pi&#92;sigma^2}} &#92;int_{-&#92;infty}^&#92;infty dx&#92;; e^{-(x-&#92;mu)^2/2&#92;sigma^2} e^{ikx}' title='&#92;displaystyle F(k) = &#92;frac{1}{&#92;sqrt{2&#92;pi&#92;sigma^2}} &#92;int_{-&#92;infty}^&#92;infty dx&#92;; e^{-(x-&#92;mu)^2/2&#92;sigma^2} e^{ikx}' class='latex' />.</p>
<p>The exponentials inside the integral can be turned into a single Gaussian by completing squares:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+-+%5Cfrac%7B+%28x-%5Cmu%29%5E2%7D%7B2%5Csigma%5E2%7D+%2B+ikx+%3D+-+%5Cfrac%7B+%28x-%5Cmu-ik%5Csigma%5E2%29%5E2%7D%7B2%5Csigma%5E2%7D+%2B+ik%5Cmu+-+%5Cfrac%7Bk%5E2%5Csigma%5E2%7D%7B2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle - &#92;frac{ (x-&#92;mu)^2}{2&#92;sigma^2} + ikx = - &#92;frac{ (x-&#92;mu-ik&#92;sigma^2)^2}{2&#92;sigma^2} + ik&#92;mu - &#92;frac{k^2&#92;sigma^2}{2}' title='&#92;displaystyle - &#92;frac{ (x-&#92;mu)^2}{2&#92;sigma^2} + ikx = - &#92;frac{ (x-&#92;mu-ik&#92;sigma^2)^2}{2&#92;sigma^2} + ik&#92;mu - &#92;frac{k^2&#92;sigma^2}{2}' class='latex' />.</p>
<p>The remaining integral in <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x' title='x' class='latex' /> can be easily solved as <a href="http://neotropic.wordpress.com/2010/12/10/integral-of-a-gaussian-function/">the integral of a Gaussian</a>:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+F%28k%29+%3D+%5Cfrac%7B1%7D%7B%5Csqrt%7B2%5Cpi%5Csigma%5E2%7D%7D+e%5E%7Bik%5Cmu%7D+e%5E%7B-k%5E2%5Csigma%5E2%2F2%7D+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+e%5E%7B-%28x-%5Cmu%2Bik%5Csigma%5E2%29%5E2%2F2%5Csigma%5E2%7D+e%5E%7Bikx%7D+%3D+e%5E%7Bik%5Cmu%7D+e%5E%7B-k%5E2%5Csigma%5E2%2F2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle F(k) = &#92;frac{1}{&#92;sqrt{2&#92;pi&#92;sigma^2}} e^{ik&#92;mu} e^{-k^2&#92;sigma^2/2} &#92;int_{-&#92;infty}^&#92;infty dx&#92;; e^{-(x-&#92;mu+ik&#92;sigma^2)^2/2&#92;sigma^2} e^{ikx} = e^{ik&#92;mu} e^{-k^2&#92;sigma^2/2}' title='&#92;displaystyle F(k) = &#92;frac{1}{&#92;sqrt{2&#92;pi&#92;sigma^2}} e^{ik&#92;mu} e^{-k^2&#92;sigma^2/2} &#92;int_{-&#92;infty}^&#92;infty dx&#92;; e^{-(x-&#92;mu+ik&#92;sigma^2)^2/2&#92;sigma^2} e^{ikx} = e^{ik&#92;mu} e^{-k^2&#92;sigma^2/2}' class='latex' />.</p>
<p>This is simply another Gaussian function:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cboxed%7B+%5Cdisplaystyle+F%28k%29+%3D+e%5E%7B-%5Cmu%5E2%2F2%5Csigma%5E2%7D+%5Cexp%5Cleft%5C%7B+-+%5Cfrac%7B%28k-i%5Cmu%2F%5Csigma%5E2%29%5E2+%5Csigma%5E2%7D%7B2%7D+%5Cright%5C%7D+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;boxed{ &#92;displaystyle F(k) = e^{-&#92;mu^2/2&#92;sigma^2} &#92;exp&#92;left&#92;{ - &#92;frac{(k-i&#92;mu/&#92;sigma^2)^2 &#92;sigma^2}{2} &#92;right&#92;} }' title='&#92;boxed{ &#92;displaystyle F(k) = e^{-&#92;mu^2/2&#92;sigma^2} &#92;exp&#92;left&#92;{ - &#92;frac{(k-i&#92;mu/&#92;sigma^2)^2 &#92;sigma^2}{2} &#92;right&#92;} }' class='latex' />.</p>
<br />Filed under: <a href='http://neotropic.wordpress.com/category/mathematics/statistics/'>Statistics</a>  <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gocomments/neotropic.wordpress.com/2248/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/comments/neotropic.wordpress.com/2248/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godelicious/neotropic.wordpress.com/2248/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/delicious/neotropic.wordpress.com/2248/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gofacebook/neotropic.wordpress.com/2248/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/facebook/neotropic.wordpress.com/2248/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gotwitter/neotropic.wordpress.com/2248/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/twitter/neotropic.wordpress.com/2248/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gostumble/neotropic.wordpress.com/2248/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/stumble/neotropic.wordpress.com/2248/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godigg/neotropic.wordpress.com/2248/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/digg/neotropic.wordpress.com/2248/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/goreddit/neotropic.wordpress.com/2248/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/reddit/neotropic.wordpress.com/2248/" /></a> <img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=neotropic.wordpress.com&amp;blog=18211513&amp;post=2248&amp;subd=neotropic&amp;ref=&amp;feed=1" width="1" height="1" />]]></content:encoded>
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			<media:title type="html">phalacrocorax</media:title>
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		<title>Exponential of a projector</title>
		<link>http://neotropic.wordpress.com/2011/07/20/exponential-of-a-projector/</link>
		<comments>http://neotropic.wordpress.com/2011/07/20/exponential-of-a-projector/#comments</comments>
		<pubDate>Wed, 20 Jul 2011 18:17:19 +0000</pubDate>
		<dc:creator>phalacrocorax</dc:creator>
				<category><![CDATA[Linear Algebra]]></category>

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		<description><![CDATA[Let be a scalar and be a projector, thus satisfying for every . An exponential of can be expanded in a power series: . Recognizing that the series in the last right-hand term can be interpreted as another exponential with subtracted, we find: . Filed under: Linear Algebra<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=neotropic.wordpress.com&amp;blog=18211513&amp;post=2244&amp;subd=neotropic&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Let <img src='http://s0.wp.com/latex.php?latex=%5Ctheta&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;theta' title='&#92;theta' class='latex' /> be a scalar and <img src='http://s0.wp.com/latex.php?latex=P&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='P' title='P' class='latex' /> be a projector, thus satisfying <img src='http://s0.wp.com/latex.php?latex=P%5En+%3D+P&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='P^n = P' title='P^n = P' class='latex' /> for every <img src='http://s0.wp.com/latex.php?latex=n%5Cge+1&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='n&#92;ge 1' title='n&#92;ge 1' class='latex' />. An exponential of <img src='http://s0.wp.com/latex.php?latex=%5Ctheta+P&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;theta P' title='&#92;theta P' class='latex' /> can be expanded in a power series:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+e%5E%7B%5Ctheta+P%7D+%3D+%5Csum_%7Bn%3D0%7D%5E%5Cinfty+%5Cfrac%7B%5Ctheta%5En+P%5En%7D%7Bn%21%7D+%3D+1%2B%5Csum_%7Bn%3D1%7D%5E%5Cinfty+%5Cfrac%7B%5Ctheta%5En%7D%7Bn%21%7D+P+&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle e^{&#92;theta P} = &#92;sum_{n=0}^&#92;infty &#92;frac{&#92;theta^n P^n}{n!} = 1+&#92;sum_{n=1}^&#92;infty &#92;frac{&#92;theta^n}{n!} P ' title='&#92;displaystyle e^{&#92;theta P} = &#92;sum_{n=0}^&#92;infty &#92;frac{&#92;theta^n P^n}{n!} = 1+&#92;sum_{n=1}^&#92;infty &#92;frac{&#92;theta^n}{n!} P ' class='latex' />.</p>
<p>Recognizing that the series in the last right-hand term can be interpreted as another exponential with <img src='http://s0.wp.com/latex.php?latex=1&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='1' title='1' class='latex' /> subtracted, we find:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cboxed%7B+%5Cdisplaystyle+e%5E%7B%5Ctheta+P%7D+%3D+1%2B+%28e%5E%7B%5Ctheta%7D+-1%29P+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;boxed{ &#92;displaystyle e^{&#92;theta P} = 1+ (e^{&#92;theta} -1)P }' title='&#92;boxed{ &#92;displaystyle e^{&#92;theta P} = 1+ (e^{&#92;theta} -1)P }' class='latex' />.</p>
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			<media:title type="html">phalacrocorax</media:title>
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		<title>Gaussian probability distribution</title>
		<link>http://neotropic.wordpress.com/2011/07/20/gaussian-probability-distribution/</link>
		<comments>http://neotropic.wordpress.com/2011/07/20/gaussian-probability-distribution/#comments</comments>
		<pubDate>Wed, 20 Jul 2011 15:06:11 +0000</pubDate>
		<dc:creator>phalacrocorax</dc:creator>
				<category><![CDATA[Statistics]]></category>

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		<description><![CDATA[A Gaussian probability distribution will be proportional to a generic Gaussian function: , where and . According to the integral of the Gaussian over the real line, the normalization of this function must be: . Therefore, the constant must be : . Now, the first moment of this distribution can be calculated from the integral [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=neotropic.wordpress.com&amp;blog=18211513&amp;post=2235&amp;subd=neotropic&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>A Gaussian probability distribution <img src='http://s0.wp.com/latex.php?latex=P%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='P(x)' title='P(x)' class='latex' /> will be proportional to a generic Gaussian function:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+P%28x%29+%3D+C+e%5E%7B-a%28x-b%29%5E2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle P(x) = C e^{-a(x-b)^2}' title='&#92;displaystyle P(x) = C e^{-a(x-b)^2}' class='latex' />,</p>
<p>where <img src='http://s0.wp.com/latex.php?latex=a+%3E+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='a &gt; 0' title='a &gt; 0' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=b+%5Cge+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='b &#92;ge 0' title='b &#92;ge 0' class='latex' />.</p>
<p>According to the <a href="http://neotropic.wordpress.com/2010/12/10/integral-of-a-gaussian-function/">integral of the Gaussian over the real line</a>, the normalization of this function must be:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+P%28x%29+%3D+C+%5Csqrt%7B+%5Cfrac%7B%5Cpi%7D%7Ba%7D+%7D+%3D+1&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; P(x) = C &#92;sqrt{ &#92;frac{&#92;pi}{a} } = 1' title='&#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; P(x) = C &#92;sqrt{ &#92;frac{&#92;pi}{a} } = 1' class='latex' />.</p>
<p>Therefore, the constant <img src='http://s0.wp.com/latex.php?latex=C&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='C' title='C' class='latex' /> must be <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7Ba%2F%5Cpi%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;sqrt{a/&#92;pi}' title='&#92;sqrt{a/&#92;pi}' class='latex' />:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+P%28x%29+%3D+%5Csqrt%7B+%5Cfrac%7Ba%7D%7B%5Cpi%7D%7D+e%5E%7B-a%28x-b%29%5E2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle P(x) = &#92;sqrt{ &#92;frac{a}{&#92;pi}} e^{-a(x-b)^2}' title='&#92;displaystyle P(x) = &#92;sqrt{ &#92;frac{a}{&#92;pi}} e^{-a(x-b)^2}' class='latex' />.</p>
<p>Now, the <a href="http://neotropic.wordpress.com/2011/01/10/moments/">first moment</a> of this distribution can be calculated from the <a href="http://neotropic.wordpress.com/2011/07/15/integral-of-a-gaussian-multiplied-by-a-power-over-the-real-line/">integral of a power multiplied by a Gaussian</a>:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cmu+%3D+%5Cdisplaystyle+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+x+P%28x%29+%3D+b&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mu = &#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x P(x) = b' title='&#92;mu = &#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x P(x) = b' class='latex' />.</p>
<p>The second moment may be calculated using the same formula:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cmu_2+%3D+%5Cdisplaystyle+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+x%5E2+P%28x%29+%3D+b%5E2+%2B+%5Cfrac%7B1%7D%7B2a%7D+&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mu_2 = &#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^2 P(x) = b^2 + &#92;frac{1}{2a} ' title='&#92;mu_2 = &#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^2 P(x) = b^2 + &#92;frac{1}{2a} ' class='latex' />.</p>
<p>According to the definition of <a href="http://neotropic.wordpress.com/2010/12/11/variance/">variance</a>, its value will be:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Csigma%5E2+%3D+%5Cmu_2+-+%5Cmu%5E2+%3D+%5Cfrac%7B1%7D%7B2a%7D+&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;sigma^2 = &#92;mu_2 - &#92;mu^2 = &#92;frac{1}{2a} ' title='&#92;displaystyle &#92;sigma^2 = &#92;mu_2 - &#92;mu^2 = &#92;frac{1}{2a} ' class='latex' />.</p>
<p>In this way, we can write this distribution in terms of its average value <img src='http://s0.wp.com/latex.php?latex=%5Cmu&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mu' title='&#92;mu' class='latex' /> and its variance <img src='http://s0.wp.com/latex.php?latex=%5Csigma%5E2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;sigma^2' title='&#92;sigma^2' class='latex' />:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cboxed%7B+%5Cdisplaystyle+P%28x%29+%3D+%5Cfrac%7B+1+%7D%7B%5Csqrt%7B2+%5Cpi+%5Csigma%5E2%7D%7D++e%5E%7B-%28x-%5Cmu%29%5E2%2F2%5Csigma%5E2%7D+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;boxed{ &#92;displaystyle P(x) = &#92;frac{ 1 }{&#92;sqrt{2 &#92;pi &#92;sigma^2}}  e^{-(x-&#92;mu)^2/2&#92;sigma^2} }' title='&#92;boxed{ &#92;displaystyle P(x) = &#92;frac{ 1 }{&#92;sqrt{2 &#92;pi &#92;sigma^2}}  e^{-(x-&#92;mu)^2/2&#92;sigma^2} }' class='latex' />.</p>
<br />Filed under: <a href='http://neotropic.wordpress.com/category/mathematics/statistics/'>Statistics</a>  <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gocomments/neotropic.wordpress.com/2235/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/comments/neotropic.wordpress.com/2235/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godelicious/neotropic.wordpress.com/2235/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/delicious/neotropic.wordpress.com/2235/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gofacebook/neotropic.wordpress.com/2235/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/facebook/neotropic.wordpress.com/2235/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gotwitter/neotropic.wordpress.com/2235/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/twitter/neotropic.wordpress.com/2235/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gostumble/neotropic.wordpress.com/2235/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/stumble/neotropic.wordpress.com/2235/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godigg/neotropic.wordpress.com/2235/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/digg/neotropic.wordpress.com/2235/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/goreddit/neotropic.wordpress.com/2235/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/reddit/neotropic.wordpress.com/2235/" /></a> <img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=neotropic.wordpress.com&amp;blog=18211513&amp;post=2235&amp;subd=neotropic&amp;ref=&amp;feed=1" width="1" height="1" />]]></content:encoded>
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			<media:title type="html">phalacrocorax</media:title>
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		<title>Conservative forces</title>
		<link>http://neotropic.wordpress.com/2011/07/17/conservative-forces/</link>
		<comments>http://neotropic.wordpress.com/2011/07/17/conservative-forces/#comments</comments>
		<pubDate>Sun, 17 Jul 2011 17:04:57 +0000</pubDate>
		<dc:creator>phalacrocorax</dc:creator>
				<category><![CDATA[Classical Mechanics]]></category>

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		<description><![CDATA[A conservative force is a position-dependent force that can be expressed as the negative gradient of a scalar potential : . The work exerted by this force depends only on the value of the potential at the initial point and at the final position , as we conclude by applying Gauss&#8217;s theorem: . As the [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=neotropic.wordpress.com&amp;blog=18211513&amp;post=2230&amp;subd=neotropic&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>A conservative force <img src='http://s0.wp.com/latex.php?latex=%5Cmathbf%7BF%7D%28%5Cmathbf%7Br%7D%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathbf{F}(&#92;mathbf{r})' title='&#92;mathbf{F}(&#92;mathbf{r})' class='latex' /> is a position-dependent force that can be expressed as the negative gradient of a scalar potential <img src='http://s0.wp.com/latex.php?latex=U%28%5Cmathbf%7Br%7D%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='U(&#92;mathbf{r})' title='U(&#92;mathbf{r})' class='latex' />:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cboxed%7B+%5Cdisplaystyle+%5Cmathbf%7BF%7D%28%5Cmathbf%7Br%7D%29+%3D+-+%5Cboldsymbol%5Cnabla+U%28%5Cmathbf%7Br%7D%29+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;boxed{ &#92;displaystyle &#92;mathbf{F}(&#92;mathbf{r}) = - &#92;boldsymbol&#92;nabla U(&#92;mathbf{r}) }' title='&#92;boxed{ &#92;displaystyle &#92;mathbf{F}(&#92;mathbf{r}) = - &#92;boldsymbol&#92;nabla U(&#92;mathbf{r}) }' class='latex' />.</p>
<p>The <a href="http://neotropic.wordpress.com/2011/07/17/work/">work</a> exerted by this force depends only on the value of the potential at the initial point <img src='http://s0.wp.com/latex.php?latex=%5Cmathbf%7Br%7D_i&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathbf{r}_i' title='&#92;mathbf{r}_i' class='latex' /> and at the final position <img src='http://s0.wp.com/latex.php?latex=%5Cmathbf%7Br%7D_f&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathbf{r}_f' title='&#92;mathbf{r}_f' class='latex' />, as we conclude by applying Gauss&#8217;s theorem:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+W+%3D+-+%5Cint_%7B%5Cmathbf%7Br%7D_i%7D%5E%7B%5Cmathbf%7Br%7D_f%7D+d%5Cmathbf%7Bs%7D+%5Ccdot+%5Cboldsymbol%5Cnabla+U%28%5Cmathbf%7Br%7D%29+%3D+-+U%28%5Cmathbf%7Br%7D_f%29+%2B+U%28%5Cmathbf%7Br%7D_i%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle W = - &#92;int_{&#92;mathbf{r}_i}^{&#92;mathbf{r}_f} d&#92;mathbf{s} &#92;cdot &#92;boldsymbol&#92;nabla U(&#92;mathbf{r}) = - U(&#92;mathbf{r}_f) + U(&#92;mathbf{r}_i)' title='&#92;displaystyle W = - &#92;int_{&#92;mathbf{r}_i}^{&#92;mathbf{r}_f} d&#92;mathbf{s} &#92;cdot &#92;boldsymbol&#92;nabla U(&#92;mathbf{r}) = - U(&#92;mathbf{r}_f) + U(&#92;mathbf{r}_i)' class='latex' />.</p>
<p>As the work is equivalent to change in kinetic energy <img src='http://s0.wp.com/latex.php?latex=T_f+-+T_i&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='T_f - T_i' title='T_f - T_i' class='latex' />, we find the following law of conservation for the total energy of the system:</p>
<p><img src='http://s0.wp.com/latex.php?latex=T_f+%2B+U%28%5Cmathbf%7Br%7D_f%29+%3D+T_i+%2B+U%28%5Cmathbf%7Br%7D_i%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='T_f + U(&#92;mathbf{r}_f) = T_i + U(&#92;mathbf{r}_i)' title='T_f + U(&#92;mathbf{r}_f) = T_i + U(&#92;mathbf{r}_i)' class='latex' />.</p>
<p>Therefore, a conservative force field keeps constant the total (kinetic plus potential) energy of the system.</p>
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			<media:title type="html">phalacrocorax</media:title>
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		<title>Work exerted on a particle</title>
		<link>http://neotropic.wordpress.com/2011/07/17/work/</link>
		<comments>http://neotropic.wordpress.com/2011/07/17/work/#comments</comments>
		<pubDate>Sun, 17 Jul 2011 14:31:32 +0000</pubDate>
		<dc:creator>phalacrocorax</dc:creator>
				<category><![CDATA[Classical Mechanics]]></category>

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		<description><![CDATA[The work exerted by a force on a particle over a path is simply its line integral over the path. Formally, . If is the total force exerted on the particle, Newton&#8217;s second law and the fact that give us: , where is the initial time and is the end time of the particle&#8217;s trajectory, [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=neotropic.wordpress.com&amp;blog=18211513&amp;post=2225&amp;subd=neotropic&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>The work exerted by a force <img src='http://s0.wp.com/latex.php?latex=%5Cmathbf%7BF%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathbf{F}' title='&#92;mathbf{F}' class='latex' /> on a particle over a path <img src='http://s0.wp.com/latex.php?latex=C&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='C' title='C' class='latex' /> is simply its line integral over the path. Formally,</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cboxed%7B+%5Cdisplaystyle+W_C+%5Cequiv+%5Cint_C+d%5Cmathbf%7Bs%7D+%5Ccdot+%5Cmathbf%7BF%7D+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;boxed{ &#92;displaystyle W_C &#92;equiv &#92;int_C d&#92;mathbf{s} &#92;cdot &#92;mathbf{F} }' title='&#92;boxed{ &#92;displaystyle W_C &#92;equiv &#92;int_C d&#92;mathbf{s} &#92;cdot &#92;mathbf{F} }' class='latex' />.</p>
<p>If <img src='http://s0.wp.com/latex.php?latex=%5Cmathbf%7BF%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathbf{F}' title='&#92;mathbf{F}' class='latex' /> is the total force exerted on the particle, <a href="http://neotropic.wordpress.com/2011/02/01/newtons-second-law/">Newton&#8217;s second law</a> and the fact that <img src='http://s0.wp.com/latex.php?latex=d%5Cmathbf%7Bs%7D+%3D+%5Cmathbf%7Bv%7D+dt&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='d&#92;mathbf{s} = &#92;mathbf{v} dt' title='d&#92;mathbf{s} = &#92;mathbf{v} dt' class='latex' /> give us:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+W_C+%3D+%5Cint_%7Bt_i%7D%5E%7Bt_f%7D+dt+%5C%3B+m+%5Cmathbf%7Bv%7D+%5Ccdot%5Cfrac%7Bd%7D%7Bdt%7D+%5Cmathbf%7Bv%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle W_C = &#92;int_{t_i}^{t_f} dt &#92;; m &#92;mathbf{v} &#92;cdot&#92;frac{d}{dt} &#92;mathbf{v}' title='&#92;displaystyle W_C = &#92;int_{t_i}^{t_f} dt &#92;; m &#92;mathbf{v} &#92;cdot&#92;frac{d}{dt} &#92;mathbf{v}' class='latex' />,</p>
<p>where <img src='http://s0.wp.com/latex.php?latex=t_1&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t_1' title='t_1' class='latex' /> is the initial time and <img src='http://s0.wp.com/latex.php?latex=t_2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t_2' title='t_2' class='latex' /> is the end time of the particle&#8217;s trajectory, and we are supposing that the particle&#8217;s mass is constant. As it is obvious that:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cmathbf%7Bv%7D+%5Ccdot%5Cfrac%7Bd%7D%7Bdt%7D+%5Cmathbf%7Bv%7D+%3D+%5Cfrac%7B1%7D%7B2%7D+%5Cfrac%7Bd%7D%7Bdt%7D+v%5E2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;mathbf{v} &#92;cdot&#92;frac{d}{dt} &#92;mathbf{v} = &#92;frac{1}{2} &#92;frac{d}{dt} v^2' title='&#92;displaystyle &#92;mathbf{v} &#92;cdot&#92;frac{d}{dt} &#92;mathbf{v} = &#92;frac{1}{2} &#92;frac{d}{dt} v^2' class='latex' />,</p>
<p>the work can be expressed as:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+W_C+%3D+%5Cfrac%7Bm%7D%7B2%7D+%5Cint_%7Bt_i%7D%5E%7Bt_f%7D+dt+%5C%3B+%5Cfrac%7Bd%7D%7Bdt%7D+v%5E2+%3D++%5Cfrac%7Bm+v%5E2+%28t_f%29%7D%7B2%7D+-++%5Cfrac%7Bm+v%5E2+%28t_i%29%7D%7B2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle W_C = &#92;frac{m}{2} &#92;int_{t_i}^{t_f} dt &#92;; &#92;frac{d}{dt} v^2 =  &#92;frac{m v^2 (t_f)}{2} -  &#92;frac{m v^2 (t_i)}{2}' title='&#92;displaystyle W_C = &#92;frac{m}{2} &#92;int_{t_i}^{t_f} dt &#92;; &#92;frac{d}{dt} v^2 =  &#92;frac{m v^2 (t_f)}{2} -  &#92;frac{m v^2 (t_i)}{2}' class='latex' />.</p>
<p>This means that the total work exerted on the particle is the same as the change in its kinetic energy.</p>
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		<title>Integral of a centered Gaussian multiplied by a power over the real line</title>
		<link>http://neotropic.wordpress.com/2011/07/15/integral-of-a-centered-gaussian-multiplied-by-a-power-over-the-real-line/</link>
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		<pubDate>Fri, 15 Jul 2011 20:48:50 +0000</pubDate>
		<dc:creator>phalacrocorax</dc:creator>
				<category><![CDATA[Integral Zoo]]></category>

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		<description><![CDATA[We will call those Gaussian functions symmetric in respect with the origin the centered Gaussians. The most general form of the integrals of such centered functions multiplied by powers of is: . Using the result of the general case on the right-hand side, we find: . The only term in the summation that does not [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=neotropic.wordpress.com&amp;blog=18211513&amp;post=2216&amp;subd=neotropic&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>We will call those Gaussian functions symmetric in respect with the origin the centered Gaussians. The most general form of the integrals of such centered functions multiplied by powers of <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x' title='x' class='latex' /> is:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+x%5En+e%5E%7B-ax%5E2%7D+%3D+%5Clim_%7Bb%5Cto+0%7D+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+x%5En+e%5E%7B-a%28x-b%29%5E2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^n e^{-ax^2} = &#92;lim_{b&#92;to 0} &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^n e^{-a(x-b)^2}' title='&#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^n e^{-ax^2} = &#92;lim_{b&#92;to 0} &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^n e^{-a(x-b)^2}' class='latex' />.</p>
<p>Using <a href="http://neotropic.wordpress.com/2011/07/15/integral-of-a-gaussian-multiplied-by-a-power-over-the-real-line/">the result of the general case</a> on the right-hand side, we find:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+x%5En+e%5E%7B-ax%5E2%7D+%3D+%5Clim_%7Bb%5Cto+0%7D+%5Csqrt%7B+%5Cfrac%7B+%5Cpi%7D%7Ba%7D+%7D++%5Csum_%7Bq%3D0%7D%5E%7B%5Bn%2F2%5D%7D++%5Cfrac%7Bn%21+b%5En%7D%7Bq%21%28n-2q%29%21%7D+%5Cleft%28+%5Cfrac%7B1%7D%7B4ab%5E2%7D+%5Cright%29%5Eq+&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^n e^{-ax^2} = &#92;lim_{b&#92;to 0} &#92;sqrt{ &#92;frac{ &#92;pi}{a} }  &#92;sum_{q=0}^{[n/2]}  &#92;frac{n! b^n}{q!(n-2q)!} &#92;left( &#92;frac{1}{4ab^2} &#92;right)^q ' title='&#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^n e^{-ax^2} = &#92;lim_{b&#92;to 0} &#92;sqrt{ &#92;frac{ &#92;pi}{a} }  &#92;sum_{q=0}^{[n/2]}  &#92;frac{n! b^n}{q!(n-2q)!} &#92;left( &#92;frac{1}{4ab^2} &#92;right)^q ' class='latex' />.</p>
<p>The only term in the summation that does not vanish is the one where <img src='http://s0.wp.com/latex.php?latex=2q%3Dn&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='2q=n' title='2q=n' class='latex' />. This is only possible if <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='n' title='n' class='latex' /> is an even number (<img src='http://s0.wp.com/latex.php?latex=n%3D2m&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='n=2m' title='n=2m' class='latex' />):</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+x%5E%7B2m%7D+e%5E%7B-ax%5E2%7D+%3D+%5Csqrt%7B+%5Cfrac%7B+%5Cpi%7D%7Ba%7D+%7D++%5Cfrac%7B%282m%29%21%7D%7Bm%21%7D+%5Cleft%28+%5Cfrac%7B1%7D%7B4a%7D+%5Cright%29%5Em+&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^{2m} e^{-ax^2} = &#92;sqrt{ &#92;frac{ &#92;pi}{a} }  &#92;frac{(2m)!}{m!} &#92;left( &#92;frac{1}{4a} &#92;right)^m ' title='&#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^{2m} e^{-ax^2} = &#92;sqrt{ &#92;frac{ &#92;pi}{a} }  &#92;frac{(2m)!}{m!} &#92;left( &#92;frac{1}{4a} &#92;right)^m ' class='latex' />,</p>
<p>which is the same as:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cboxed%7B+%5Cdisplaystyle+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+x%5E%7B2m%7D+e%5E%7B-ax%5E2%7D+%3D+%5Csqrt%7B+%5Cfrac%7B+%5Cpi%7D%7Ba%7D+%7D+%5Cfrac%7B%282m-1%29%21%21%7D%7B%282a%29%5Em%7D+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;boxed{ &#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^{2m} e^{-ax^2} = &#92;sqrt{ &#92;frac{ &#92;pi}{a} } &#92;frac{(2m-1)!!}{(2a)^m} }' title='&#92;boxed{ &#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^{2m} e^{-ax^2} = &#92;sqrt{ &#92;frac{ &#92;pi}{a} } &#92;frac{(2m-1)!!}{(2a)^m} }' class='latex' />.</p>
<p>The odd case, where the terms in the summation vanish, is obviously null:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cboxed%7B+%5Cdisplaystyle+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+x%5E%7B2m%2B1%7D+e%5E%7B-ax%5E2%7D+%3D+0+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;boxed{ &#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^{2m+1} e^{-ax^2} = 0 }' title='&#92;boxed{ &#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^{2m+1} e^{-ax^2} = 0 }' class='latex' />.</p>
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			<media:title type="html">phalacrocorax</media:title>
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		<title>Integral of a Gaussian multiplied by a power over the real line</title>
		<link>http://neotropic.wordpress.com/2011/07/15/integral-of-a-gaussian-multiplied-by-a-power-over-the-real-line/</link>
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		<pubDate>Fri, 15 Jul 2011 20:20:01 +0000</pubDate>
		<dc:creator>phalacrocorax</dc:creator>
				<category><![CDATA[Integral Zoo]]></category>

		<guid isPermaLink="false">http://neotropic.wordpress.com/?p=2177</guid>
		<description><![CDATA[The general form of the integral of a Gaussian multiplied by the th power of the variable over the whole real line is: . The first thing we must do is change variables to , arriving at: . Therefore, we just need to solve the integrals , which are: . These integrals vanish when is [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=neotropic.wordpress.com&amp;blog=18211513&amp;post=2177&amp;subd=neotropic&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>The general form of the integral of a Gaussian multiplied by the <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='n' title='n' class='latex' />th power of the variable <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x' title='x' class='latex' /> over the whole real line is:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+I_n+%28a%2Cb%29+%5Cequiv+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+x%5En+e%5E%7B-a%28x-b%29%5E2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle I_n (a,b) &#92;equiv &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^n e^{-a(x-b)^2}' title='&#92;displaystyle I_n (a,b) &#92;equiv &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^n e^{-a(x-b)^2}' class='latex' />.</p>
<p>The first thing we must do is change variables to <img src='http://s0.wp.com/latex.php?latex=x%5E%5Cprime+%3D+x-b&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x^&#92;prime = x-b' title='x^&#92;prime = x-b' class='latex' />, arriving at:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+I_n%28a%2Cb%29+%3D+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5E%5Cprime+%5C%3B+%28x%5E%5Cprime+%2B+b%29%5En+e%5E%7B-a%7Bx%5E%5Cprime%7D%5E2+%7D+%3D+%5Csum_%7Bm%3D0%7D%5En+%5Cleft%28+%5Cbegin%7Barray%7D%7Bc%7D+n%5C%5C+m%5Cend%7Barray%7D+%5Cright%29+I_m%28a%2C0%29+b%5E%7Bn-m%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle I_n(a,b) = &#92;int_{-&#92;infty}^&#92;infty dx^&#92;prime &#92;; (x^&#92;prime + b)^n e^{-a{x^&#92;prime}^2 } = &#92;sum_{m=0}^n &#92;left( &#92;begin{array}{c} n&#92;&#92; m&#92;end{array} &#92;right) I_m(a,0) b^{n-m}' title='&#92;displaystyle I_n(a,b) = &#92;int_{-&#92;infty}^&#92;infty dx^&#92;prime &#92;; (x^&#92;prime + b)^n e^{-a{x^&#92;prime}^2 } = &#92;sum_{m=0}^n &#92;left( &#92;begin{array}{c} n&#92;&#92; m&#92;end{array} &#92;right) I_m(a,0) b^{n-m}' class='latex' />.</p>
<p>Therefore, we just need to solve the integrals <img src='http://s0.wp.com/latex.php?latex=I_m%28a%2C0%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='I_m(a,0)' title='I_m(a,0)' class='latex' />, which are:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+I_m%28a%2C0%29+%3D+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+x%5Em+e%5E%7B-ax%5E2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle I_m(a,0) = &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^m e^{-ax^2}' title='&#92;displaystyle I_m(a,0) = &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^m e^{-ax^2}' class='latex' />.</p>
<p>These integrals vanish when <img src='http://s0.wp.com/latex.php?latex=m&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='m' title='m' class='latex' /> is an odd number, as this would turn the integrand into an odd function. Therefore, we just need to be concerned about the functions where <img src='http://s0.wp.com/latex.php?latex=m%3D2q&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='m=2q' title='m=2q' class='latex' />, with <img src='http://s0.wp.com/latex.php?latex=q+%5Cin+%5Cmathbb%7BN%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='q &#92;in &#92;mathbb{N}' title='q &#92;in &#92;mathbb{N}' class='latex' />:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+I_%7B2q%7D%28a%2C0%29+%3D+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+x%5E%7B2q%7D+e%5E%7B-ax%5E2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle I_{2q}(a,0) = &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^{2q} e^{-ax^2}' title='&#92;displaystyle I_{2q}(a,0) = &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^{2q} e^{-ax^2}' class='latex' />.</p>
<p>The trick now is to notice that we can express the integrand as a partial derivative of a simpler function:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle++x%5E%7B2q%7D+e%5E%7B-ax%5E2%7D+%3D+%28-1%29%5Eq+%5Cfrac%7B%5Cpartial%5Eq%7D%7B%5Cpartial+a%5Eq%7D+e%5E%7B-ax%5E2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle  x^{2q} e^{-ax^2} = (-1)^q &#92;frac{&#92;partial^q}{&#92;partial a^q} e^{-ax^2}' title='&#92;displaystyle  x^{2q} e^{-ax^2} = (-1)^q &#92;frac{&#92;partial^q}{&#92;partial a^q} e^{-ax^2}' class='latex' />.</p>
<p>The last term on the right-hand side is simply <a href="http://neotropic.wordpress.com/2010/12/10/integral-of-a-gaussian-function/">an integral of a Gaussian</a>:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle++I_%7B2q%7D%28a%2C0%29+%3D+%28-1%29%5Eq+%5Cfrac%7B%5Cpartial%5Eq%7D%7B%5Cpartial+a%5Eq%7D+%5Csqrt%7B+%5Cfrac%7B%5Cpi%7D%7Ba%7D+%7D+%3D+%5Cfrac%7B%282q-1%29%21%21%7D%7B%282a%29%5Eq%7D+%5Csqrt%7B+%5Cfrac%7B+%5Cpi%7D%7Ba%7D+%7D+%3D+%5Cfrac%7B%282q%29%21%7D%7Bq%21%284a%29%5Eq%7D+%5Csqrt%7B+%5Cfrac%7B+%5Cpi%7D%7Ba%7D+%7D+&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle  I_{2q}(a,0) = (-1)^q &#92;frac{&#92;partial^q}{&#92;partial a^q} &#92;sqrt{ &#92;frac{&#92;pi}{a} } = &#92;frac{(2q-1)!!}{(2a)^q} &#92;sqrt{ &#92;frac{ &#92;pi}{a} } = &#92;frac{(2q)!}{q!(4a)^q} &#92;sqrt{ &#92;frac{ &#92;pi}{a} } ' title='&#92;displaystyle  I_{2q}(a,0) = (-1)^q &#92;frac{&#92;partial^q}{&#92;partial a^q} &#92;sqrt{ &#92;frac{&#92;pi}{a} } = &#92;frac{(2q-1)!!}{(2a)^q} &#92;sqrt{ &#92;frac{ &#92;pi}{a} } = &#92;frac{(2q)!}{q!(4a)^q} &#92;sqrt{ &#92;frac{ &#92;pi}{a} } ' class='latex' />.</p>
<p>Replacing it in the original expression for the integral, we find:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+I_n%28a%2Cb%29+%3D+%5Csum_%7Bq%3D0%7D%5E%7B%5Bn%2F2%5D%7D+%5Cleft%28+%5Cbegin%7Barray%7D%7Bc%7D+n%5C%5C+2q%5Cend%7Barray%7D+%5Cright%29++%5Cfrac%7B%282q%29%21%7D%7Bq%21%284a%29%5Eq%7D+%5Csqrt%7B+%5Cfrac%7B+%5Cpi%7D%7Ba%7D+%7D+b%5E%7Bn-2q%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle I_n(a,b) = &#92;sum_{q=0}^{[n/2]} &#92;left( &#92;begin{array}{c} n&#92;&#92; 2q&#92;end{array} &#92;right)  &#92;frac{(2q)!}{q!(4a)^q} &#92;sqrt{ &#92;frac{ &#92;pi}{a} } b^{n-2q}' title='&#92;displaystyle I_n(a,b) = &#92;sum_{q=0}^{[n/2]} &#92;left( &#92;begin{array}{c} n&#92;&#92; 2q&#92;end{array} &#92;right)  &#92;frac{(2q)!}{q!(4a)^q} &#92;sqrt{ &#92;frac{ &#92;pi}{a} } b^{n-2q}' class='latex' />,</p>
<p>or</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cboxed%7B+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+x%5En+e%5E%7B-a%28x-b%29%5E2%7D+%3D++%5Csqrt%7B+%5Cfrac%7B+%5Cpi%7D%7Ba%7D+%7D++%5Csum_%7Bq%3D0%7D%5E%7B%5Bn%2F2%5D%7D++%5Cfrac%7Bn%21+b%5En%7D%7Bq%21%28n-2q%29%21%7D+%5Cleft%28+%5Cfrac%7B1%7D%7B4ab%5E2%7D+%5Cright%29%5Eq+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;boxed{ &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^n e^{-a(x-b)^2} =  &#92;sqrt{ &#92;frac{ &#92;pi}{a} }  &#92;sum_{q=0}^{[n/2]}  &#92;frac{n! b^n}{q!(n-2q)!} &#92;left( &#92;frac{1}{4ab^2} &#92;right)^q }' title='&#92;displaystyle &#92;boxed{ &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^n e^{-a(x-b)^2} =  &#92;sqrt{ &#92;frac{ &#92;pi}{a} }  &#92;sum_{q=0}^{[n/2]}  &#92;frac{n! b^n}{q!(n-2q)!} &#92;left( &#92;frac{1}{4ab^2} &#92;right)^q }' class='latex' />.</p>
<h3>Results for the first powers</h3>
<table>
<tr>
<td><img src='http://s0.wp.com/latex.php?latex=%5Cmathbf%7B+n%3D0+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathbf{ n=0 }' title='&#92;mathbf{ n=0 }' class='latex' />:</td>
<td> <img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+e%5E%7B-a%28x-b%29%5E2%7D+%3D+%5Csqrt%7B+%5Cfrac%7B%5Cpi%7D%7Ba%7D+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; e^{-a(x-b)^2} = &#92;sqrt{ &#92;frac{&#92;pi}{a} }' title='&#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; e^{-a(x-b)^2} = &#92;sqrt{ &#92;frac{&#92;pi}{a} }' class='latex' /></td>
<td>(<a href="http://neotropic.wordpress.com/2010/12/10/integral-of-a-gaussian-function/">Integral of a Gaussian</a>)</td>
</tr>
<tr>
<td><img src='http://s0.wp.com/latex.php?latex=%5Cmathbf%7B+n%3D1+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathbf{ n=1 }' title='&#92;mathbf{ n=1 }' class='latex' />:</td>
<td> <img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+x+e%5E%7B-a%28x-b%29%5E2%7D+%3D+%5Csqrt%7B+%5Cfrac%7B%5Cpi%7D%7Ba%7D+%7D+%5Cleft%5B+b+%5Cright%5D++&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x e^{-a(x-b)^2} = &#92;sqrt{ &#92;frac{&#92;pi}{a} } &#92;left[ b &#92;right]  ' title='&#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x e^{-a(x-b)^2} = &#92;sqrt{ &#92;frac{&#92;pi}{a} } &#92;left[ b &#92;right]  ' class='latex' /></td>
<td /></tr>
<tr>
<td><img src='http://s0.wp.com/latex.php?latex=%5Cmathbf%7B+n%3D2+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathbf{ n=2 }' title='&#92;mathbf{ n=2 }' class='latex' />:</td>
<td> <img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+x%5E2+e%5E%7B-a%28x-b%29%5E2%7D+%3D+%5Csqrt%7B+%5Cfrac%7B%5Cpi%7D%7Ba%7D+%7D+%5Cleft%5B+b%5E2+%2B+%5Cfrac%7B1%7D%7B2a%7D+%5Cright%5D+&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^2 e^{-a(x-b)^2} = &#92;sqrt{ &#92;frac{&#92;pi}{a} } &#92;left[ b^2 + &#92;frac{1}{2a} &#92;right] ' title='&#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^2 e^{-a(x-b)^2} = &#92;sqrt{ &#92;frac{&#92;pi}{a} } &#92;left[ b^2 + &#92;frac{1}{2a} &#92;right] ' class='latex' /></td>
<td /></tr>
<tr>
<td><img src='http://s0.wp.com/latex.php?latex=%5Cmathbf%7B+n%3D3+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathbf{ n=3 }' title='&#92;mathbf{ n=3 }' class='latex' />:</td>
<td> <img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+x%5E3+e%5E%7B-a%28x-b%29%5E2%7D+%3D+%5Csqrt%7B+%5Cfrac%7B%5Cpi%7D%7Ba%7D+%7D+%5Cleft%5B+b%5E3+%2B+3b+%5Cfrac%7B1%7D%7B2a%7D+%5Cright%5D+&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^3 e^{-a(x-b)^2} = &#92;sqrt{ &#92;frac{&#92;pi}{a} } &#92;left[ b^3 + 3b &#92;frac{1}{2a} &#92;right] ' title='&#92;displaystyle &#92;int_{-&#92;infty}^&#92;infty dx&#92;; x^3 e^{-a(x-b)^2} = &#92;sqrt{ &#92;frac{&#92;pi}{a} } &#92;left[ b^3 + 3b &#92;frac{1}{2a} &#92;right] ' class='latex' /></td>
<td /></tr>
</table>
<br />Filed under: <a href='http://neotropic.wordpress.com/category/mathematics/calculus/integral-zoo/'>Integral Zoo</a>  <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gocomments/neotropic.wordpress.com/2177/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/comments/neotropic.wordpress.com/2177/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godelicious/neotropic.wordpress.com/2177/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/delicious/neotropic.wordpress.com/2177/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gofacebook/neotropic.wordpress.com/2177/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/facebook/neotropic.wordpress.com/2177/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gotwitter/neotropic.wordpress.com/2177/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/twitter/neotropic.wordpress.com/2177/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gostumble/neotropic.wordpress.com/2177/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/stumble/neotropic.wordpress.com/2177/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godigg/neotropic.wordpress.com/2177/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/digg/neotropic.wordpress.com/2177/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/goreddit/neotropic.wordpress.com/2177/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/reddit/neotropic.wordpress.com/2177/" /></a> <img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=neotropic.wordpress.com&amp;blog=18211513&amp;post=2177&amp;subd=neotropic&amp;ref=&amp;feed=1" width="1" height="1" />]]></content:encoded>
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			<media:title type="html">phalacrocorax</media:title>
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		<title>Malthusian growth model</title>
		<link>http://neotropic.wordpress.com/2011/07/12/malthusian-growth-model/</link>
		<comments>http://neotropic.wordpress.com/2011/07/12/malthusian-growth-model/#comments</comments>
		<pubDate>Wed, 13 Jul 2011 02:13:28 +0000</pubDate>
		<dc:creator>phalacrocorax</dc:creator>
				<category><![CDATA[Calculus]]></category>

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		<description><![CDATA[The Malthusian growth model for a population states that the number of individuals at instant , represented by the non-negative function , has a rate of change directly proportional to the current population: , where is a positive real number. This differential equation is solved by an exponential function: . The result for this model [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=neotropic.wordpress.com&amp;blog=18211513&amp;post=2166&amp;subd=neotropic&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>The Malthusian growth model for a population states that the number of individuals at instant <img src='http://s0.wp.com/latex.php?latex=t&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t' title='t' class='latex' />, represented by the non-negative function <img src='http://s0.wp.com/latex.php?latex=p%28t%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='p(t)' title='p(t)' class='latex' />, has a rate of change directly proportional to the current population:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdt%7D+p%28t%29+%3D+a+p%28t%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dt} p(t) = a p(t)' title='&#92;displaystyle &#92;frac{d}{dt} p(t) = a p(t)' class='latex' />,</p>
<p>where <img src='http://s0.wp.com/latex.php?latex=a&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='a' title='a' class='latex' /> is a positive real number.</p>
<p>This <a href="http://neotropic.wordpress.com/2011/07/09/solution-of-a-homogeneous-first-order-differential-equation/">differential equation is solved</a> by an exponential function:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cboxed%7B+%5Cdisplaystyle+p%28t%29+%3D+e%5E%7Bat%7D+p%280%29+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;boxed{ &#92;displaystyle p(t) = e^{at} p(0) }' title='&#92;boxed{ &#92;displaystyle p(t) = e^{at} p(0) }' class='latex' />.</p>
<p>The result for this model is a rapidly growing population.</p>
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			<media:title type="html">phalacrocorax</media:title>
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		<title>Linearity of an average value</title>
		<link>http://neotropic.wordpress.com/2011/07/11/linearity-of-an-average-value/</link>
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		<pubDate>Mon, 11 Jul 2011 18:40:18 +0000</pubDate>
		<dc:creator>phalacrocorax</dc:creator>
				<category><![CDATA[Statistics]]></category>

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		<description><![CDATA[The average value of a function of a random variable is given by the following integral of the function multiplied by the probability density : . As long as each average value of a series of functions exists, the average value of any linear combination of these functions will be linear: , which is the [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=neotropic.wordpress.com&amp;blog=18211513&amp;post=2155&amp;subd=neotropic&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>The <a href="http://neotropic.wordpress.com/2011/01/10/average-value/">average value</a> of a function <img src='http://s0.wp.com/latex.php?latex=f%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f(x)' title='f(x)' class='latex' /> of a <a href="http://neotropic.wordpress.com/2011/07/11/continuous-random-variable/">random variable</a> <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x' title='x' class='latex' /> is given by the following integral of the function multiplied by the probability density <img src='http://s0.wp.com/latex.php?latex=p%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='p(x)' title='p(x)' class='latex' />:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cleft%5Clangle+f%28x%29+%5Cright%5Crangle+%3D+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+f%28x%29+p%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;left&#92;langle f(x) &#92;right&#92;rangle = &#92;int_{-&#92;infty}^&#92;infty dx&#92;; f(x) p(x)' title='&#92;displaystyle &#92;left&#92;langle f(x) &#92;right&#92;rangle = &#92;int_{-&#92;infty}^&#92;infty dx&#92;; f(x) p(x)' class='latex' />.</p>
<p>As long as each average value of a series of functions <img src='http://s0.wp.com/latex.php?latex=f_1%28x%29%2C+f_2%28x%29%2C+%5Cldots&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f_1(x), f_2(x), &#92;ldots' title='f_1(x), f_2(x), &#92;ldots' class='latex' /> exists, the average value of any <a href="http://neotropic.wordpress.com/2011/03/14/linear-combination/">linear combination</a> of these functions will be linear:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cleft%5Clangle+%5Csum_i+c_i+f_i%28x%29+%5Cright%5Crangle+%3D+%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+%5Csum_i+c_i+f_i%28x%29+p%28x%29+%3D+%5Csum_i+c_i++%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty+dx%5C%3B+f_i%28x%29+p%28x%29+&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;left&#92;langle &#92;sum_i c_i f_i(x) &#92;right&#92;rangle = &#92;int_{-&#92;infty}^&#92;infty dx&#92;; &#92;sum_i c_i f_i(x) p(x) = &#92;sum_i c_i  &#92;int_{-&#92;infty}^&#92;infty dx&#92;; f_i(x) p(x) ' title='&#92;displaystyle &#92;left&#92;langle &#92;sum_i c_i f_i(x) &#92;right&#92;rangle = &#92;int_{-&#92;infty}^&#92;infty dx&#92;; &#92;sum_i c_i f_i(x) p(x) = &#92;sum_i c_i  &#92;int_{-&#92;infty}^&#92;infty dx&#92;; f_i(x) p(x) ' class='latex' />,</p>
<p>which is the same as:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cboxed%7B+%5Cdisplaystyle+%5Cleft%5Clangle+%5Csum_i+c_i+f_i%28x%29+%5Cright%5Crangle+%3D++%5Csum_i+c_i++%5Cleft%5Clangle+f_i%28x%29+%5Cright%5Crangle+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;boxed{ &#92;displaystyle &#92;left&#92;langle &#92;sum_i c_i f_i(x) &#92;right&#92;rangle =  &#92;sum_i c_i  &#92;left&#92;langle f_i(x) &#92;right&#92;rangle }' title='&#92;boxed{ &#92;displaystyle &#92;left&#92;langle &#92;sum_i c_i f_i(x) &#92;right&#92;rangle =  &#92;sum_i c_i  &#92;left&#92;langle f_i(x) &#92;right&#92;rangle }' class='latex' />.</p>
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